Why doesn't this loop work?

[nevets04]

Code:

#include <iostream>
using namespace std;int main(){int x=1;while(x<=99){x=x+1;cout<<x<< endl;return 0;}}

The output is 2, why isn't it:
2
3
4
5
6
7
8
9
10
etc...

[Gaijin]

Because you return the function within the while loop....

Your code

Code:

return 0;}}

Right code

Code:

}return 0;}

[Etheryte]

Using return will stop the program in it's track, no matter what operation it's currently undergoing. For example, you can use return 1 for error checking.

[MrD.]

Code:

#include <iostream>
using namespace std;int main(){int x=1;while(x<=99){x=x+1;cout<<x<< endl;return 0;}}

Please tell me you don't really lay your code out like that?

Code:

#include <iostream>
using namespace std;

int main()
{
    int x=1;
    while(x<=99)
    {
        x=x+1;
        cout<<x<< endl;
        return 0;
    }
}

Makes it much clearer why it is going wrong (because return is inside the loop). Also you might want to look into a for loop (and pre/post increment operators).

Code:

#include <iostream>
using namespace std;

int main()
{
    for(int x = 1; x <= 99; ++x)
        cout << x << endl;
    return 0;
}

[nevets04]

Please tell me you don't really lay your code out like that?

Code:

#include <iostream>
using namespace std;

int main()
{
    int x=1;
    while(x<=99)
    {
        x=x+1;
        cout<<x<< endl;
        return 0;
    }
}

Makes it much clearer why it is going wrong (because return is inside the loop). Also you might want to look into a for loop (and pre/post increment operators).

Code:

#include <iostream>
using namespace std;

int main()
{
    for(int x = 1; x <= 99; ++x)
        cout << x << endl;
    return 0;
}

I do that for shorter programs

[Sagittarius]

so so simple...

your return 0; will return to OS ... not return to loop