Introduction to Python List Comprehensions

[uber1337]

map/filter equivalent:

Code:

sum = []
for x in range(1000):
    sum.append(x)
sum = filter(lambda x : x % 3 == 0 or x % 5 == 0, sum)
sum = reduce(lambda x, y: x + y, sum)
print sum

Yep. Your way is better ;)

Edit:
One liner FTW!

Code:

reduce(lambda x,y : x+y, [x for x in xrange(1000) if x % 3 == 0 or x % 5 == 0])