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Switch Conditionals in Functions not working????
#2
That's not how you call a function, you just use the name, no need to specify the return type when calling it, just do:
Code:
case '1':  // Case for choosing the good alignment
    cout << "You have chosen to join the sides of good...\n\n";
    FUNC_RACE_GOOD(); // Call the good race function
    
    break;
Not even sure how that compiled.
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RE: Switch Conditionals in Functions not working???? - by MrD. - 01-22-2010, 08:08 PM

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