11-30-2010, 07:42 PM
(10-20-2010, 08:25 AM)Disease Wrote: I believe you made an error in your post, or there's a discrepancy in the problem itself. If the problem wants to you find four consecutive integers then it'd be:Exactly what I was going to post. I am in algebra 1 also, and we are learning this crap. I got a 98 in it last quarter. too easy imo.
x
x + 1
x + 2
x + 3
By jumping immediately from x to (x + 2) you're breaking consecution. Regardless, you need to write out the equation based on what they've given you. You know that it's the sum of four consecutive integers, represented by x, which each iteration adding one more than the last. Thus the problem can be represented as:
x + (x + 1) + (x + 2) + (x + 3) = 94
And of course you can simplify that equation.
4x + 6 = 94
4x = 88
x = 22
Then check your answer:
x + (x + 1) + (x + 2) + (x + 3)
22 + (22 + 1) + (22 + 2) + (22 + 3)
22 + 23 + 24 + 25 = 94