Switch Conditionals in Functions not working????

[Equinøx]

Hey everbody

I am having a problem with a switch conditional which calls a function

The function is

Code:

char FUNC_RACE_GOOD();

it is declared in the switch conditional like this

Code:

case '1':  // Case for choosing the good alignment
    cout << "You have chosen to join the sides of good...\n\n";
    char FUNC_RACE_GOOD(); // Call the good race function
    
    break;

And end up here

Code:

char FUNC_RACE_GOOD() { // Function race good

    char RACE;

    cout << "----------------------------------\n";
    cout << "               Races\n";
    cout << "----------------------------------\n\n\n";
    cout << "1. Elf\n";
    cout << "2. Human\n";
    cout << "3. Dwarf\n";
    cout << "----------------------------------\n";
    cout << "Enter the corresponding digit for your race...\n\n";
    cout << "Race: \n";
    cin >> RACE;
// Not finished yet

but all it does it completely skip the whole function call and just ends the program

any help?

[MrD.]

That's not how you call a function, you just use the name, no need to specify the return type when calling it, just do:

Code:

case '1':  // Case for choosing the good alignment
    cout << "You have chosen to join the sides of good...\n\n";
    FUNC_RACE_GOOD(); // Call the good race function
    
    break;

Not even sure how that compiled.

[Fallen]

yeah when calling a function, its name() will suffice. no need to add the data type

[Thirteen]

Wouldn't you want the function to return something aswell?

[MrD.]

The function would still return something, whether you choose to do anything with it is up to you. If you wanted the value that function returns you would just do:

Code:

char returned = FUNC_RACE_GOOD(); // Call the good race function, storing the return value in 'returned'