12-18-2009, 11:14 PM
I couldn't figure it out and was hoping you guys could.
9x 7i < 3(3x 7u)
Also, first thread.
9x 7i < 3(3x 7u)
Also, first thread.
Difficult High School Equation
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12-18-2009, 11:14 PM
I couldn't figure it out and was hoping you guys could.
9x 7i < 3(3x 7u) Also, first thread.
Whoever gave you that equation is a nerd.
I'm going to assume that you typed it wrong and that it was supposed to be: 9x-7i > 3(3x-7u). I'm also going to assume that the variable "i" doesn't stand for the imaginary number √-1. Why am I making so many assumptions you ask? 9x-7i > 3(3x-7u) 9x-7i > 9x - 21u -7i > -21u i < 3u ...aka "i <3 u" btw, Google is your friend. http://www.google.com/search?rlz=1C1GGLS...C+3(3x+7u)
Robert Picard
http://www.rpicard.net
12-20-2009, 06:41 PM
(12-20-2009, 06:24 PM)Rob Wrote: Whoever gave you that equation is a nerd.It was meant as a first post for the forum, I already knew the solution.
Oh, that's lame...
Robert Picard
http://www.rpicard.net
12-20-2009, 11:15 PM
Hahaha, niice man.
02-25-2010, 11:23 PM
hahaha wat type of math is that?
04-07-2010, 01:08 PM
Difficult equation? That's easier then the easiest equations we had on our algebra test this semester. And i'm only 16.. (Dunno what grade as i'm from sweden and don't know the US grade system.)
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