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+---- Thread: Calculator v1 (/showthread.php?tid=3300)
RE: Calculator v1 - Brainless Control - 12-05-2009
Oh!,well that's ok I guess,not a big deal is it? :S
RE: Calculator v1 - M4X1MU5 - 12-12-2009
Thank's Xenocide i will give a try later
RE: Calculator v1 - nextlive - 12-24-2009
its easy to make but for a beginner its good
RE: Calculator v1 - Brainless Control - 01-09-2010
Update:
Ok so I'm back from holidays,I was kinda bored today so I decided to add a goto statement in it to re-do the put new number thing and not exit and re-open the program to do it.
Code:
#include <iostream>
using namespace std;
int main()
{
double a,b;
int option;
labelgoto:
cout << ":::Calculator v1::: \n";
cout << "Enter a Number: \n";
cin >> a;
cout << "Enter a Number: \n";
cin >> b;
do {
cout << "1. Multiplication \n";
cout << "2. Division \n";
cout << "3. Addition \n";
cout << "4. Subtraction \n";
cout << "5. Enter new numbers \n";
cout << "6. Quit \n";
do {
cout << "Enter your choice: ";
cin >> option;
} while(option<1 || option>6);
switch (option) {
case 1:
cout << "The Result is: " << a*b << '\n';
break;
case 2:
cout << "The Result is: " << a/b << '\n';
break;
case 3:
cout << "The Result is: " << a+b << '\n';
break;
case 4:
cout << "The Result is: " << a-b << '\n';
break;
case 5:
goto labelgoto;
break;
case 6:
cout << "Goodbye \n";
break;
}
} while(option!=6);
return 0;
}RE: Calculator v1 - MrD. - 01-09-2010
(01-09-2010, 07:23 AM)Beta™ Wrote: I decided to add a goto statement
No! Goto statements are considered bad practice in C++ because they cause spagetti-code. Use some other form of conditional statement where possible.
Quote:The primary problem with goto is that it allows a programmer to cause the point of execution to jump around the code arbitrarily. This creates what is not-so-affectionately known as spaghetti code. Spaghetti code has a path of execution that resembles a bowl of spaghetti (all tangled and twisted), making it extremely difficult to follow the logic of such code.
As Dijkstra says somewhat humorously, "the quality of programmers is a decreasing function of the density of go to statements in the programs they produce".
To read Dijkstra's paper, click here.
RE: Calculator v1 - Brainless Control - 01-10-2010
Yeah I kinda know it's bad thing to use in your code but I couldn't find any other way.
Thanks for the link MrD. I'll read it.
RE: Calculator v1 - Gaijin - 01-10-2010
What do you think about packing it into 2 function, void showMenu() and int Calculate()
Then you can use the while statement in the main function to loop whole day through your code.
RE: Calculator v1 - Brainless Control - 01-10-2010
Is it possible to do this?
Well it won't compile cause I'm getting only 1 error.
Quote:error C2447: '{' : missing function header (old-style formal list?)
Code:
#include <iostream>
using namespace std;
void myfunc();
void myfuncc();
int main()
{
double a,b;
int option;
myfuncc();
{
cout << ":::Calculator v1::: \n";
cout << "Enter a Number: \n";
cin >> a;
cout << "Enter a Number: \n";
cin >> b;
do {
cout << "1. Multiplication \n";
cout << "2. Division \n";
cout << "3. Addition \n";
cout << "4. Subtraction \n";
cout << "5. Enter new numbers \n";
cout << "6. Quit \n";
do {
cout << "Enter your choice: ";
cin >> option;
} while(option<1 || option>6);
switch (option) {
case 1:
cout << "The Result is: " << a*b << '\n';
break;
case 2:
cout << "The Result is: " << a/b << '\n';
break;
case 3:
cout << "The Result is: " << a+b << '\n';
break;
case 4:
cout << "The Result is: " << a-b << '\n';
break;
case 5:
myfunc();
break;
case 6:
cout << "Goodbye \n";
break;
}
} while(option!=6);
return 0;
}
}
void myfunc();
{
myfuncc();
}RE: Calculator v1 - Gaijin - 01-10-2010
Here I don't have the time to debug your code, but I have an modification to offer you ;)
Compiled and works as you wanted it to!
Code:
#include <iostream>
using namespace std;
int option = 0;
double a = 0;
double b = 0;
int showMenu()
{
cout << ":::Calculator v1::: \n";
cout << "Enter a Number: \n";
cin >> a;
cout << "Enter a Number: \n";
cin >> b;
cout << "1. Multiplication \n";
cout << "2. Division \n";
cout << "3. Addition \n";
cout << "4. Subtraction \n";
cout << "5. Enter new numbers \n";
cout << "6. Quit \n";
cout << "Enter your choice: ";
cin >> option;
return option;
}
void Calc(int option, double num1, double num2) {
a = num1;
b = num2;
switch (option) {
case 1:
cout << "The Result is: " << a*b << '\n';
break;
case 2:
cout << "The Result is: " << a/b << '\n';
break;
case 3:
cout << "The Result is: " << a+b << '\n';
break;
case 4:
cout << "The Result is: " << a-b << '\n';
break;
case 5:
break;
case 6:
cout << "Goodbye \n";
break;
}
}
int main()
{
do {
option = showMenu();
do {
Calc(option, a, b);
} while(option<1 || option>6);
} while(option!=6);
return 0;
}RE: Calculator v1 - Brainless Control - 01-10-2010
(01-10-2010, 05:58 AM)Master of the Universe Wrote: Here I don't have the time to debug your code, but I have an modification to offer you ;)or that lol,very smart move
Compiled and works as you wanted it to!
Code:#include <iostream>
using namespace std;
int option = 0;
double a = 0;
double b = 0;
int showMenu()
{
cout << ":::Calculator v1::: \n";
cout << "Enter a Number: \n";
cin >> a;
cout << "Enter a Number: \n";
cin >> b;
cout << "1. Multiplication \n";
cout << "2. Division \n";
cout << "3. Addition \n";
cout << "4. Subtraction \n";
cout << "5. Enter new numbers \n";
cout << "6. Quit \n";
cout << "Enter your choice: ";
cin >> option;
return option;
}
void Calc(int option, double num1, double num2) {
a = num1;
b = num2;
switch (option) {
case 1:
cout << "The Result is: " << a*b << '\n';
break;
case 2:
cout << "The Result is: " << a/b << '\n';
break;
case 3:
cout << "The Result is: " << a+b << '\n';
break;
case 4:
cout << "The Result is: " << a-b << '\n';
break;
case 5:
break;
case 6:
cout << "Goodbye \n";
break;
}
}
int main()
{
do {
option = showMenu();
do {
Calc(option, a, b);
} while(option<1 || option>6);
} while(option!=6);
return 0;
}
