Support Forums - Help me, I am about to punch a whole in my wall.

Okay I'm trying to use this php upload script. But I keep getting this error. "Sorry, there was a problem uploading your file."

here is my code

upload.html

Code:
<form enctype="multipart/form-data" action="upload.php" method="POST">

Please choose a file: <input name="uploaded" type="file" /><br />

<input type="submit" value="Upload" />

</form>

upload.php

Code:
<?php 

 $target = "home/users/web/b60/moo.tdrunner95com/ideviceforums.net/packages_upload/"; 

 $target = $target . basename( $_files['uploaded']['name']) ; 

 $ok=1; 

 //Here we check that $ok was not set to 0 by an error 

 if ($ok==0) 

 { 

 Echo "Sorry your file was not uploaded"; 

 } 

 //If everything is ok we try to upload it 

 else 

 { 

 if(move_uploaded_file($_files['uploaded']['tmp_name'], $target)) 

 { 

 echo "The file ". basename( $_files['uploadedfile']['name']). " has been uploaded"; 

 } 

 else 

 { 

 echo "Sorry, there was a problem uploading your file."; 

 } 

 } 

 ?>

PLEASE HELP ME!

I'm really sorry if this doesn't help, but I don't know PHP at all ><

Where is $ok declared? I think the problem you're having is just because it's value is 0.

(02-22-2012, 04:10 PM)Valderino Wrote: [ -> ]I'm really sorry if this doesn't help, but I don't know PHP at all ><

Where is $ok declared? I think the problem you're having is just because it's value is 0.

No its value if 1... Its checking to see if the value is 0.

(02-22-2012, 04:12 PM)iRun Wrote: [ -> ]No its value if 1... Its checking to see if the value is 0.

OH! I totally skipped that line. >< ($ok=1;)

I'm just making wild guesses here, but I guess it's better than nothing... why not try:

declare(ok=1);